Question

Suma a patru numere naturale consecutive este 50 . Aflati numerele .
Repede pls ! E urgent

Answer 1

a+b+c+d=50

a,b,c,d-consecutive=>b=a+1, c=a+2, d=a+3

a+a+1+a+2+a+3=50

4a+6=50

4a=44

a=11, b=12, c=13, d=14

Answer 2

Vom folosi Met.figurativa

a,b,c,d=nr. Consecutive

a/___/

b/___/+1 50

c/___/+1+1

d/___/+1+1+1

50-(1×6)=

50-6=44

A=44÷4

A=11

B=11×1+1

B=12

C=11×1+1+1

C=13

D=11×1+1+1+1

D=14

VERIFICARE:

11+12+13+14=

23+13+14=

36+14= 5 0