Question

suma a patru numere naturale este 67.Daca din fiecare se scade acelasi numar,se obtin numerele:9,15,11,12.Afla cele 4 numere.

Answer 1

a+b+c+d=67
a-x=9
b-x=15
c-x=11
d-x=12
_____
a-x+b-x+c-x+d-x=47
67-4x=47
4x=20
x=5

=>a=14
b=20
c=16
d=17

Answer 2

a+b+c+d= 67
a-x=9⇒a=9+x
b-x=15⇒b=15+x
c-x=11⇒c=11+x
d-x=12⇒d=12+x
9+x+15+x+11+x+12+x=67
4x=67-12-11-15-9
4x=20
x=5
a=9+5=14
b=15+5=20
c=11+5=16
d=12+5=17
Proba 14+20+16+17=67