Question

Suma a patru numere naturale este 67 daca din fiecare se scade acelasi nr se obtin numerele 9,15,11 si 12

Answer 1

a+b+c+d=67
a-x=9 => a=9+x
b-x=15 => b=15+x
c-x=11 => c=11+x
d-x=12 => d=12+x
(9+x)+(15+x)+(11+x)+(12+x)=67
4x+47=67
4x=20
x=5

a = 9+5 = 14
b = 15+5 = 20
c = 11+5 = 16
d = 12+5 = 17
Verificare : 14+20+16+17= 67

Answer 2

a+b+c+d=67
9+15+11+12=47
67-47=20
20:4=5
a=9+5. b=15+5. c=11+5. d=12+5
14+20+16+17=67