Question

Suma a petru numere consecutive este 908.Aflati numerele

Answer 1

(a+1) + (a+2) +(a+3)+(a+4)=908
=>a+a+a+a=908-10
=>4*a=898
=>a=224 r 2=> F
Acum luam doar nr pare
consecutive.
(a+2)+(a+4)+(a+6)+(a+8)=908
4*a=908-20
4*a=888
a=222
b=224
c=226
d=228