Question

Suma a sase numere este 171 fiecare numar este 7mai mic decat procedentul determinati cele sase numere

Answer 1

a+b+c+d+e+f=171
b=a-7
c=b-7=a-7-7=a-14
d=c-7=a-14-7=a-21
e=d-7=a-21-7=a-28
f=e-7=a-28-7=a-35
a+a-7+a-14+a-21+a-28+a-35=171
6a-105=171
6a=171+105
6a=276
a=276/6
a=46
b=a-7=46-7=39
b=39
c=46-14=32
c=32
d=46-21=25
d=25
e=46-28=18
e=18
f=46-35=11
f=11
46+39+32+25+18+11=171