Question

suma a trei nr.consecutive impare este4305.Sa se afle numerele?

Answer 1

Notam cu A,b,c cele trei nr. a+b+c=4305. b=a+2,c=a+4. 3a +6 =4305 .3a =4299 . a=1433 . b=1435 . c=1437

Answer 2

2k-1+2k+1+2k+3=4305
6k=4305-3=4302
k=4302:6= 717
n1=2k-1= 2*717 -1=1433
n2=2k+1= 2*717 + 1=1435
n3=2k+3= 2*717 + 3=1437
----------------------------------------
verificare n1+n2+n3=4305 ok.