Question

suma a trei nr este 104,28 daca din fiecare se scade acelasi nr natural se obtin nr : 19,57 19,89 19,82 . determinati nr initial

Answer 1

|+||+|||=104,28

| =!__!+19,57
||= !__!+19,89
|||=!__!+19,82
104,28-(19,57+19,89+19,82)=104,28-59,28=45
45:3=15-numarul care se scade
|=15+19,57=34,57
||=15+19,89=34,89
|||=15+19,82=34,82
Proba:34,57+34,89+34,82=104,28