Question

suma a trei nr. este 1676.Daca din fiecare se scade acelasi nr se obtin nr.252, 410 , 114.Determinati nr.

Answer 1

a+b+c= 1676
dar a-x= 252 => a= 252+x
b-x= 410 => b=410+x
c-x= 114 => c= 114+x
inlocuim in prima relatie si avem
252+x+410+x+114+x=1676
3x+776=1676
3x=1676-776=900
x=900:3=300
acum avem a=252+x=252+300=552
b=410+x=410+300=710
c=114+x=114+300=414
verificare: 552+710+414=1676

Answer 2

a+b+c=1676
a-n=252
b-n=410
c-n=114
252+410+114=776
1676-776=900
900:3=300
a=300+252=552
b=300+410=710
c=300+114=414
v:552+710+414=1676