Question

suma a trei nr este 23320.suma primelor doua nr este 13746 iar suma ultimelor 2 nr este cu 3660 mai mare ,care sunt cele 3 nr?

Answer 1

x+y+z = 23320

x+y = 13746

y+z = 3660+13746

y+z = 17406

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13746+ z = 23320

z= 23320-13746

*z= 9574*

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y+9574=17406

y=17406-9574

*y=7832*

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x+17406 = 23320

x=23320-17406

*x = 5914*

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Răspuns: x= 5914 ; y = 7832 ; z = 9574

Proba: 5914 + 7832 + 9574 = 23320 Adevărat