Question

Suma a trei nr este 255,a-14,b-4,c+9,sunt nr consecutive iar c+9este crl mai mic.Aglati cele 3 nr

Answer 1

a+b+c=255
I)c+9=d
a-14=d+1
b-4=d+2
a+b+c+9-14-4=3*d+3
II)c+9=d
b-4=d+1
a-14=d+2
a+b+c+9-14-4=3*d+3
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225-9=3*d+3
225-9-3=3*d
243=3*d
d=81
c+9=81
c=72
a-14=82(I)sau a-14=83(II)
a=96 sau a=97
b-4=82 (II)sau b-4=83(I)
b=86 sau b=87