Question

suma a trei nr.este 478.suma primelor doua nr este 222 iar suma ultimelor doua nr este 354.determina fiecare. nr

Answer 1

a+b+c=478
a+b=222
b+c=354

222+c=478
c=478-222
c=256

b+256=354
b=354-256
b=98

a+98=222
a=222-98
a=124

V: a+b+c=478
124+98+256=478

Answer 2

a + b + c = 478
a + b = 222
b + c = 354
222 + c = 478
c = 478 - 222
c = 256
a + 354 = 478
a = 478 - 354
a = 124
124 + b + 256 = 478
b = 478 - 124 - 256
b = 98