Question

suma a trei nr impare consecutiv este 183. afla numerele

Answer 1

$x-nr. necunoscut \\ a=x+1-primul-numar \\ b=x+3-al-doilea-numar \\ c=x+5-al-treilea-numar \\ a+b+c=183 \\ x+1+x+3+x+5=183=\ \textgreater \ 3x=183-9=174 \\ =\ \textgreater \ x= \frac{174}{3} =58 \\ a=59 \\ b=61 \\ c=63$

Answer 2

Fie a, b=a+2, c=a+4

a+b+c=183
a+a+2+a+4=183
3a=177
a=59
b=61
c=63