Question

Suma a trei nr . nat consecutive este de 39. Nat = natural . nr = numere

Answer 1

$a+(a+1)+(a+2)=39 \\\\ 3a+3=39 \\\\ 3a=39-3 \\\\ 3a=36 \ |:3 \\\\ \boxed{a=12} \\\\ a+1=12+1 \\\\ \boxed{a+1=13} \\\\ a+2=12+2 \\\\ \boxed{a+2=14}$

Answer 2

Fie a b c cele trei numere a + a + 1 + a + 2 = 39 3a + 3 = 39 3a = 36 a = 12