Question

Suma a trei nr naturale consecutive este un nr natural s cu proprietatea 18 < s <30

Answer 1

a + a + 1 + a + 2 = 21 ; 18<21<30
3 × a = 21 - 3
3 × a = 18
a = 18 : 3
a = 6
a+1 = 7
a+2 = 8

6; 7 ; 8.


a + a + 1 +a + 2 = 24 ; 18<24<30
3×a = 24-3
a = 21:3
a = 7

7; 8; 9

a + a + 1 + a + 2 = 27 ;18<27<30
3×a = 27-3
a = 24:3
a = 8

8; 9 ; 10