Question

Suma a trei numere este 10 000.Suma dintre primul si al
doilea este 7200,iar suma dintre al doilea si al treilea numar este 5900.Sa se afle cele trei numere.
Dau coroana si 50 de puncte!!

Answer 1

a+b+c=10 000
a+b=7200
b+c=5900
a=4100
b=3100
c=2800
4100+3100+2800=10 000
4100+3100=7200
3100+2800=5900

Answer 2

Fie x, y si z cele 3 numere. $x +y+z= 10 000\\ x+y=7200 \\ =\ \textgreater \ \\ x+y+z-(x+y)=10000-7200=\ \textgreater \ z=2800$$\\ x+y+z=10000\\ y+z=5900\\=\ \textgreater \ \\ x+y+z-(y+z)=10000-5900=\ \textgreater \ x=4100$
$x+y=7200 =\ \textgreater \ 4100+y=7200=\ \textgreater \ y=7200-4100=\ \textgreater \ y=3100\\ \\Verificare:\\ 4100+3100+2800=7200+2800=10000$$x+y=7200 =\ \textgreater \ 4100+y=7200=\ \textgreater \ y=7200-4100=\ \textgreater \ y=3100\\ \\Verificare:\\ 4100+3100+2800=7200+2800=10000$