Question

suma a trei numere este 130. Stiind ca ele sunt invers proportionate cu 2,3,4 aflati numerele

Answer 1

a+b+c=130 {a+b+c} i.p {2,3,4} => a×2=b×3=c×4=k a×2=k=>a=k/2 a×2=k=>b=k/2 c×3=k=>c=k/3 c×4=k=>c=k/4 Inlocuim k/2 la puterea a 6a +k/3 la puterea a4a+k/4la puterea a3a =130la puterea a 12a 6k/12+4k/12+3k/12=1560/12 / × 12 5k+4k+3k=1560 13k=1560 K= 1560:13 K=120 Sper ca te.am ajutat

Answer 2

a+b+c=130

k/2+k/3+k/4=130 (amplificam la toate cu orice numar ca sa fie la numitor 12)

6k/12+4k/12+3k/12=1560
6k+4k+3k=1560
13k=1560/:13
k=120

a=120:6=60
b=120:4=30
c=120:3=40

Sper ca te am putut fii de folos!