Question

suma a trei numere este 256.daca impartim primul numar la al doilea,obtinem catul 2,iar daca impartim al doilea numar la al treilea obtinem catul 3 si restul 2

Answer 1

a+b+c=256

a/b = 2

b = 3c+2

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a=2b=2(3c+2) si inlocuim pe a si b, amandoua in functie de c in prima relatie:

2(3c+2) + 3c+2 +c = 256

2(3c+2) + 4c + 2 = 256 l :2

3c+2 + 2c + 1 = 128

5c = 128 - 3

5c= 125

c= 125:5 = 25, de unde

b= 3c+2 = 75+2 = 77

a= 2b = 2*77 = 154

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Verificarea nu strica niciodata:

a+b+c = 154+77+25 = 256, Uraaaaaaaaaaaaa, corect. :)

Answer 2

a + b + c = 256

a : b = 2 → a = 2b → a = 6c + 4

b : c = 3 r 2 → b = 3c + 2 | × 2 → 2b = 6c + 4

6c + 4 + 3c + 2 + c = 256

10c = 256 - ( 4 + 2 )

10c = 256 - 6

10c = 250

c = 250 : 10

c = 25

b = 25 × 3 + 2

b = 77

a = 25 × 6 + 4

a = 154