Question

Suma a trei numere este 32728 stiind ca suma primelor este 22292, iar a ultimelor doua este 20004 ,afla numerele

Answer 1

a+b+c=32728
a+b=22292
b+c=20004
a+2b+c=(a+b)+(b+c)=22292+20004=42296
b=(a+2b+c)-(a+b+c)=42296-32728=9568
a=a+b-b=22292-9568=12724
c=b+c-b=20004-9568=10436

Answer 2

a+b+c=32728

a+b = 22292

b+c = 20004

c) 32728 - c = 20004                                    b)   b + 12722= 20004

  c= 32728-20004                                                b = 20004 - 12722

   c=12722                                                           b = 7282

a )  a+7282 = 22292

      a= 22292 - 7282

      a=          15010