Question

Suma a trei numere este 366.Impartind al doilea numar la primul se obtine catul 2 si restul 7:impartind al treilea numar la al doilea se obtine catul 2 si restul 2.Aflati cele trei numere.Cine ma ajuta in dau coroana!Este urgent!

Answer 1

a + b + c = 366
b = 2a + 7
c = 2b + 2 = 2(b + 1) = 2(2a + 7 + 1) = 2(2a + 8) = 4(a + 4)

a + (2a + 7) + 4(a + 4) = 366
a + 2a + 7 + 4a + 16 = 366
7a = 366 - 23 = 343
a = 49
b = 2a + 7 = 98 + 7 = 105
c = 4(a + 4) = 4(49 + 4) =4 x 53= 212

Answer 2

a+b+c=366

b:a= 2 ( rest 7 )

c:b=2 ( rest 2)

b=2a+7

c=2b+2

a+2a+7+c=366
3a+7+2b+2=366
3a+9+2(2a+7)=366
7a+23=366
7a=366-23
7a=342
a=343:7
a=49

b:a=2 ( rest 7 )
b:49=2 ( rest 7 )
b=49X2+7
b=98+7
b=105

c : b = 2 (rest 2 )
c:105=2(rest 2)
c=210+2
c=212