Question

suma a trei numere este 412 primul numar micsorat cu 52 este egal cu jumatatea celui deal dilea numar si cu treimea celui deal treilea numar care sunt numerele.

Answer 1

a+b+c+=412
a-52=b/2⇒b=2(a-52)
a-52=c/3⇒c=3(a-52)
inlocuim in prima relatie
a+2(a-52)+3(a-52)=412
a+2a-104+3a-156=412
6a-260=412
6a=412+260
a=672/6=112
b=2(a-52)=2(112-52)=120
c=3(a-52)=3(112-52)=180
112+120+180=412

Answer 2

a+b+c=412
a-52=b/2=c/3
(a-52)+2c/3+c=412-52=360
c/3+2c/3+3c/3=360
6c/3=360
2c=360=>c=180
a=180/3+52=60+52=112
b=2X(180/3)=2X60=120