Question

Suma a trei numere este 724.Primul numar marit cu 3 este de doua ori mai mic decat al doilea numar micsorat cu 4.Al treilea numar este de 4 ori mai mare decat primul numar.Aflati numerele.

Answer 1

a+b+c=724
2 (a+3)=b-4⇒2 (a+3)+4=b
c= 4a

a+2 (a+3)+4+4a=724
5a+2a+6+4=724
7a=724-10
7a=714
a=714:7
a=102

b=2 (102+3)+4
b=2· 105+4
b=210+4
b=214

c=4·102
c=408

Answer 2

$a+b+c=724 \\\\\\ 2(a+3)=b-4 \\\\ 2a+6=b-4 \\\\ 2a=b-4-6 \\\\ 2a=b-10 \\\\ a=\frac{b-10}{2} \\\\\\ c=4a \\\\ c=\not4 * \frac{b-10}{\not2} \\\\ c=2(b-10) \\\\ c=2b-20 \\\\ \hbox{Inlocuim numerele in suma pentru a-l afla pe b:} \\\\\\ \frac{b-10}{2}+b+2b-20=724 \\\\ \frac{b-10}{2}+3b=724+20 \\\\ \frac{b-10}{2}+3b^{(2}=744^{(2} \\\\ b-10+6b=1488 \\\\ 7b=1488+10 \\\\ 7b=1498 \ \ \ |:7 \\\\ \boxed{b=214} \\\\\\ a=\frac{214-10}{2} \\\\ a=\frac{\not204}{\not2} \\\\ \boxed{a=102}$

$c=4a \\\\ c=4*102 \\\\ \boxed{c=408}$