Question

suma a trei numere este 99 aflati nr daca sunt direct proportionale cu 2; 0,5; 0,8

Answer 1

a + b + c = 99

a/2 = b/0,5 = c/0,8 = k

a = 2k

b = 0,5k

c = 0,8k

2k + 0,5k + 0,8k = 99

3,3k = 99

k = 30

a = 2k = 60

b = 0,5k = 15

c = 0,8k = 24

Answer 2

a+b+c=99, a/2=b/0.5=c/0,8, b=0,5a/2, c=0,8a/2 inlocuim b si c

in prima relatie, a+0,5a/2+0,8a/2=99, numitor comun 2, 2a+0,5a+0,8a=198, 3.3a=198, a=198/3,3=60, b=30/2=15, c=48/2=24