Question

suma a trei numere este4298. care sunt numerele daca al doilea numar este cu 18 mai mare decat o treime din primul numar si cu 12 mai mic decat al treilea nr.ajutorr

Answer 1

a+b+c=4298
b=a:3+18
b=c-12
c=b+12
3b=a+54
a=3b-54

3b-54+b+b+12=4298
5b=4298+54-12
5b=4340
b=4340:5
b=868
c=868+12
c=880

a+868+880=4298
a+1748=4298
a=4298-1748
a=2550
Succes!

Answer 2

a+b+c=4298
b=a:3+18....=> a=(b-18)*3...=> a=3b-54
b=c-12........=> c=b+12

3b-54+b+b+12=4298
5b-42=4298
5b=4298+42
5b=4340
b=4340:5
b=868
c=868+12
c=880
a=868*3-54
a=2604-54
a=2550

2550+868+880=
=3418+880
=4298

verificare

b=2550:3+18
b=850+18
b=868
b=880-12
b=868

---------------------------------------------
a) |_____|_____|_____|
b) |_____|_ |
c) |_______|_|
............................................
a=(c-18+12)*3.....=> a=(c-30)*3....=> a=3c-90
b=c-12

3c-90+c-12+c=4298
5c-102=4298
5c=4298+102
5c=4400
c=4400:5
c=880
b=880-12
b=868
a=(880-30)*3
a=850*3
a=2250