Question

Suma a trei numere naturale consecutive este 2016. Aflati numarul.

Answer 1

a+b+c=2016

a

b=a+1

c=a+2

a+a+1+a+2=2016

3a+1+2=2016

3a+3=2016

3a=2016-3

3a=2013

a=2013/3

a=671

b=671+1

b=672

c=671+2

c=673

Answer 2

a+b+c=2016
a=b+1
b=c+1

c |----------| }
b |----------|+1 } 2016
a |----------|+1+1 }

1+2=3 (surplus)
2016-3=2013 ( suma segmentelor egale )
1+1+1=3(segmente egale)
2013:3=671 (c)
671+1=672(b)
672+1=673(a)