Question

suma a trei numere naturale eate 163.scazind al treilea numar din suma primelor doua numere obtinem67.scazind primul numar din suma ultimelor doua numere,obtinem 37.determibati cele trei numere

Answer 1

a+b+c=163
(a+b)-c=67
(b+c)-a=37
a=?,b=?,c=?
a+b+c+a+b-c=163+67
2a+2b+c-c=230
2·(a+b)=230
a+b=230:2
a+b=115
115+c=163
c=163-115
c=48
a+b+c+b+c-a=163+37
2b+2c+a-a=200
2·(b+c)=200
b+c=200:2
b+c=100
a+100=163
a=163-100
a=63
63+48+b=163
111+b=163
b=163-111
b=52