Question

Suma a trei numere naturale este 163.Scazand al treilea nr din suma primelor 2 obtinem 67.Scazand primul nr din suma ultimelor 2 nr obtinem 37.Aflati nr.

Answer 1

$a+b+c=163 \\ (a+b)-c=67=\ \textgreater \ a+b=67+c =\ \textgreater \ 67+c+c=163 \\ 2c=163-67 \\ c=96:2=48\\ (b+c)-a=37=\ \textgreater \ b+c=37+a \\ a+37+a=163 \\ 2a=163-37 \\ a=126 :2=63 \\ b=163-63-48=52 \\ a=63,b=52,c=48$