Question

suma a trei numere naturale este890 .suma primelor dua numere este 430, iar suma ultimelor doua numere este 565. care sunt cele trei numere

Answer 1

a+b=430
b+c=565
a+b+c=890
a+b+b+c=430+565
a+2b+c=995
a+2b+c-a-b-c=995-890
b=105
a=430-105
a=325
c=565-105
c=460

Answer 2

a+b+c=890
a+b=430=>a=430-b =>a=430-(565-c)
b+c=565=>b=565-c


430-(565-c)+565-c+c=890

430-565+c+565-c+c=890

430+c=890

c=890-430

c=460


b=565-460
b=105


a=430-(565-c)

a=430-565+460
a=890-565
a=325