Question

Suma a trei numere pare consecutive, stiind ca, adunandu-le cu triplul sumei lor, se obtine rezultatul 528.
Va rog! Vreau clar raspunsul!

Answer 1

numar par are forma 2a

 trei numere consecutive pare sunt 2a,2a+2,2a+4
suma lor S=2a+2a+2+2a+4

2a+2a+2+2a+4+3(2a+2a+2+2a+4)=528
S+3S=528
4S=528
S=132
daca se cer numerele:
2a+2a+2+2a+4=132
6a+6=132
6a=126, a=21
numerele vor fi
42,44,46

Answer 2

triplul=528
suma lor=528:4=132
/.../
/.../+2
/.../+2+2
a+a+2+a+4=3a+6
3a+6=132
3a=126
a=126:3
a=42
b=42+2
c=42+2+2=46
verificare:
42+46+48=126
126+126x3=528