Question

suma a trei numerepare consecutive este96.Sa se afle numerele

Answer 1

• a+a+2+a+4=96 (numere pare)
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? a,a+2,a+4
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Grafic:
a: |------|
a+2: |------|2| } 96
a+4: |------|4|
3 p.e+6=96
3 p.e=96-6
3 p.e=90
1 p.e=90:3
1 p.e=30
30+2=32 (a+2)
30+4=34 (a+4)

Algebric:
a+a+2+a+4=96
3xa+6=96
3a=96-6
3a=90
a=90:3
a=30
30+2=32 (a+2)
30+4=34 (a+4)

Verificare:
30+32+34=30x3+6=90+6=96 (A)
Răspuns:
a=30
a+2=32
a+4=34
Succes !
Suzuya