Question

Suma a trei numete naturale consecutive pare este 168.determinati nunerele.

Answer 1

$a+a+2+a+4=168 \\ 3a+6=168 \\ 3a=168-6 \\ 3a=162 \\ a=162:3 \\ a=54(primul.numar) \\ a+2=54+2=56(al .doilea.numar.) \\ a+4=54+4=58(al.treilea.numar.)$

$Proba:54+56+58=168.$

Answer 2

a + b + c = 168
a = a
b = a + 2
c = a + 4
a + a + 2 + a + 4 = 168
3a = 168 - 2 - 4
3a = 168 - 6
3a = 162
a = 162 : 3
a = 54
b = 54 + 2
b = 56
c = 54 + 4
c = 58
verificam
54 + 56 + 58 = 168