Question

suma a treia nr e 947324;suma primelor doua nr e 674999;suma ultimelor doua nr e 763847.afla nt!

Answer 1

a+b+c=947324
a+b=674999
b+c=763847
a=947324-763847=183477
b=674999-183477=491522
c=763847-491522=272325

Answer 2

x,y,z numerele
x+y+z=947324
x+y=674999
y+z=763847
947324-674999=272325(z)
947324-763847=183477(x)
947324-272325-183477=491522(y)
Sper ca te-am ajutat, si ca am calculat bine!!