Question

suma atrei numere naturale consecutive se imparte la 7 si obtinem catul24 si resul 6. determinati numerele

Answer 1

(a+a+1+a+2):7=24rest6 => 3a+3=24×7+6 => 3a+3=168+6 => 3a+3=174 => 3a=171 => a=57. Nr subt 57; 58; 59

Answer 2

a+b+c=24x7+6
a+b+c=174
a+a+1+a+2=174
3a=174-3=171
a=171:3=57
b=57+1=58
c=57+2=59