Question

suma lui gauss 1+2+3+...+2014 cum se rezolva?

Answer 1

$\boxed{ \frac{n(n+1)}{2} - formula \ Gauss \ n= ultimul \ nr\ din \ sir } \\\\ \\ \frac{2014(2014+1)}{2}= \frac{2014 \cdot2015}{2}=1007 \cdot 2015 = 2029105$

Answer 2

1 +2+3+..+2014= S= 2014•2015:2 S= 1007•2015 Asa cred