Question

Suma nr naturale pare care împartite la 7 dau catul patru

Answer 1

n : 7 = 4 + rest 0,1,2,3

n = 7 x 4 + (0,1,2,3)

n₁ = 7 x 4 = 28

n₂ = 7 x 4 + 2 = 30

Cand restul e 1 sau 3 numerele devin impare

S = 28 + 30 = 58

Answer 2

a : 7 = 4 rest 0

a = 4 × 7 + 0

a = 28 + 0

a = 28

b : 7 = 4 rest 1

b = 4 × 7 + 1

b = 28 + 1

b = 29

c : 7 = 4 rest 2

c = 4 × 7 + 2

c = 28 + 2

c = 30

d : 7 = 4 rest 3

d = 4 × 7 + 3

d = 28 + 3

d = 31

e : 7 = 4 rest 4

e = 4 × 7 + 4

e = 28 + 4

e = 32

f : 7 = 4 rest 5

f = 4 × 7 + 5

f = 28 + 5

f = 33

g : 7 = 4 rest 6

g = 4 × 7 + 6

g = 28 + 6

g = 34

Suma numerelor =
28 + 29 + 30 + 31 + 32 + 33 + 34 =

57 + 30 + 31 + 32 + 33 + 34 =

87 + 31 + 32 + 33 + 34 =

118 + 32 + 33 + 34 =

150 + 33 + 34 =

183 + 34 = 217