Question

Suma perimetrelor a doua romburi este 500 .Afla laturile romburilor, stiind ca perimetrul unuia este 1/4 din perimetrul celuilalt.

Answer 1

P romb1+P romb2=500cm;
⇒Promb1=4Promb2
⇒4l1=4·4l2
⇒4l1=16l2;
⇒16l2+4l2=500cm
⇒20l2=500cm
⇒l2=25cm[latura al doilea romb];
⇒l1=[500cm-4·25cm]/4
l1=[500cm-100cm]/4
l1=400cm/4=100cm[latura primului romb];

Answer 2

Fie
P1=X
P2=Y
X+Y=500
X=Y/4
Y/4+Y=500
Y/4+4Y/4=500/4
5Y/4=500
5Y=500*4
Y=2000/5
Y=400
l1=400/4
l1=100
X+400=500
X=500-400
X=100
l2=100/4
l2=25