Question

Suma primelor 50 numerelor naturale nenule este..

Answer 1

Gauss
1+2+3+4++...+50 =
50*51/2 = 
25*51 = 1275

Answer 2

$\text{folosim Gauss} \\ \\ \boxed{ \frac{n(n+1)}{2} } \\ \\ n- ultimul \ numar\ din \ sir \\ \\ 1+2+3+...+50= \frac{50(50+1)}{2} = \frac{\not50*51}{\not2} = 25 \cdot51= 1275$