Question

sume numerelor x y si z este 130 stiind ca sunt invers proportionale cu 2 3 si 4 aflati numerele

Answer 1

2/x=3/y=4/z=k/1 => x=k/2
y=k/3 z=k/4
x+y+z=130
k/2+k/3+k/4=130
6k+4k+3k=1560
13k=1560
k=120 =>
x=120/2= 60
y=120/3= 40
z=120/4= 30