Question

Sums a patru nr. naturale consecutive este 50. Aflati numerele prin ecuatie sau inecuatie

Answer 1

a+(a+1)+(a+2)+(a+3)=50
 a+a+1+a+2+a+3=50
4a+6=50
4a=44
a=44:4
a=11
⇒a=11
 a+1=12
a+2=13
a+3=14
verificare:
11+12+13+14=50