Question

Suna a 4 numere naturale consecutive esti 50.aflati nr

Answer 1

a+b+c+d=50
a+(a+1)+(a+2)+(a+3)=50
ax4+6=50
ax4=44
a=11
11+1=12(b)
11+2=13(c)
11+3=14(d)

Answer 2

a1 + a2 + a3 + a4= 50
a (1+2+3+4)= 50
a*10=50
a=5