Question

sunt cele trei incercuite cu rosu,mersii

Answer 1

1) ㏒2(1)-㏒2(3)+㏒4(3²)=0-㏒2(3)+㏒2(3²)/㏒2(4)=-㏒2(3) +2㏒2(3)/㏒2(2²)=
-㏒2(3) +㏒2(3)=0
2) ㏒15(3).㏒5(3).㏒√3(5).(1+㏒3(5))=
 ㏒15(3).㏒5(3).㏒√3(5).[㏒3(3)+㏒3(5)]=
 ㏒15(3).㏒5(3).㏒√3(5).㏒3(15)=
 ㏒15(3).㏒5(3).㏒√3(5).1/㏒15(3) =  (se simplifica si ramane)
㏒5(3).㏒√3(5)=㏒5(3).㏒5(5)/㏒5(√3)=㏒5(3).1/㏒5(3^1/2)
 {3 la puterea 1/2}
=㏒5(3).1/ [1/2.㏒5(3)]=2
3) ㏒3(2³).㏒2(3³) -3^[㏒9(5)]
3 ^ la puterea
3㏒3(2) .3㏒2(3)-3^[㏒3(5)/㏒3(3²)]   , se foloseste formula de schimbare a bazei
9.㏒3(2).1/㏒3(2) -3^[㏒3(5)/2]=
9-√[3^(㏒3(5)]=9-√5