Question

Te rog!!.
dat un set M={0/3,1/3,2/3,3/3,4/3,5/3,6/3}
găsi: a)....b)....v)....
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Answer 1

Răspuns:

Explicație pas cu pas:

N = multimea numerelor naturale pozitive (0, 1, 2, ....)

N* = N fara 0 (1, 2, 3, 4, ....)

0/3 = 0 ∈ N

1/3

2/3

3/3 = 1 ∈ N si  N*

4/5

5/3

6/3 = 2 ∈ N si ∈ N*

___________

M ∩ N = {0/3, 3/3, 6/3}

M ∩ N* = {3/3, 6/3}

M \ N = {1/3, 2/3, 4/3, 5/3}