Question

te rog mult de tot imi rezolvi toata teza dau coroana si multe puncte

Answer 1

[tex]\it 4x^2 =6\dfrac{1}{4} \Leftrightarrow 4x^2= \dfrac{25}{4}|_{\cdot\frac{1}{4}} \Leftrightarrow x^2= \dfrac{25}{16} \Leftrightarrow \sqrt{x^2} =\sqrt{\dfrac{25}{16}} \Leftrightarrow \\\;\\ \\\;\\ \Leftrightarrow |x| = \dfrac{5}{4} \Leftrightarrow x = \pm\dfrac{5}{4}[/tex]

$\it x_1 = -\dfrac{5}{4}, \ \ \ x_2 = \dfrac{5}{4}$