Question

te rog mult















ms mult ​

Answer 1

Răspuns:

Explicație pas cu pas:

19.

a) [(7²)¹¹·7³]:[7²³·(6⁰+36¹²:6²³)]=(7²²·7³):[7²³·(1+6²⁴:6²³)]=7²⁵:[7²³·(1+6)]=

7²⁵:(7²³·7)=7²⁵:7²⁴=7

b) [(3-4¹⁵:8¹⁰)¹⁷·16²]:(2·2²·4²)³=[(3-2³⁰:2³⁰)¹⁷·2⁸]:(2³·2⁴)³=[(3-1)¹⁷·2⁸]:(2⁷)³=

(2¹⁷·2⁸):2²¹=2²⁵:2²¹=2⁴=16

c) [5²¹:(1+8¹⁰:4¹⁴)¹⁹-1]:(4¹⁵:8⁹)=[5²¹:(1+2³⁰:2²⁸)¹⁹-1]:(2³⁰:2²⁷)=[5²¹:(1+2²)¹⁹-1]:2³=(5²¹:5¹⁹-1):2³=(5²-1):2³=24:8=3

d) [(7-2⁵·8⁷:4¹³):3+1]⁴⁹:[(9²)³]⁴=[(7-2⁵·2²¹:2²⁶):3+1]⁴⁹:[(3⁴)³]⁴=

[(7-2²⁶:2²⁶):3+1]⁴⁹:(3¹²)⁴=[(7-1):3+1]⁴⁹:3⁴⁸=(6:3+1)⁴⁹:3⁴⁸=3⁴⁹:3⁴⁸=3

20.

a) 10²·[(3¹⁷+2·3¹⁷)²:27¹¹+45⁰)]=10²·[(3¹⁸)²:3³³+1]=10²·(3³⁶:3³³+1)=10²·(3³+1)=

10²·28=2800

b) [(6·5¹⁰-5¹⁰)³:25¹⁵-47⁰]·10³=[(5·5¹⁰)³:5³⁰-1]·10³=[(5¹¹)³:5³⁰-1]·10³=

(5³³:5³⁰-1)·10³=(5³-1)·10³=124·10³=124000

c) [3⁴⁴:(3¹⁰+3¹⁰+3¹⁰)⁴+7⁰]⁵¹:2⁵⁰= [3⁴⁴:(3¹¹)⁴+1]⁵¹:2⁵⁰=[3⁴⁴:3⁴⁴+1]⁵¹:2⁵⁰=(1+1)⁵¹:2⁵⁰=

2⁵¹:2⁵⁰=2

d) 27⁷:[(2¹³+2¹³+2¹⁴)³:64⁷+1]¹⁰=3²¹:[2³⁹·(1+1+2)³:(2⁶)⁷+1]¹⁰=3²¹:(2³⁹·4³:2⁴²+1)¹⁰=

3²¹:(2³⁹·2⁶:2⁴²+1)¹⁰=3²¹:(2⁴⁵:2⁴²+1)¹⁰=3²¹:(2³+1)¹⁰=3²¹:9¹⁰=3²¹:3²⁰=3