Question

tema adunarea fractilor cu numitori diferiti calculati 7pe8+1pe 2 1pe 2+ 1pe 4 3pe 10 + 2pe 5 1 pe 6 + 2pe 3 3pe 5 +1 pe 20

Answer 1

a) $\dfrac{7}{8}+{\dfrac{^{4)}1}{\ 2}} = \dfrac{7}{8}+\dfrac{4}{8}=\dfrac{7+4}{8}=\dfrac{11}{8} =1\dfrac{3}{8}$

b) $\dfrac{^{2)}1}{\ 2}+\dfrac{1}{4} = \dfrac{2}{4}+\dfrac{1}{4}=\dfrac{2+1}{4}=\dfrac{3}{4}$

c)  $\dfrac{3}{10}+\dfrac{^{2)}2} {\ 5}=\dfrac{3}{10}+\dfrac{4}{10}=\dfrac{3+4}{10}= \dfrac{7}{10}$

d)  $\dfrac{1}{6} + \dfrac{^{2)}2}{\ 3} =\dfrac{1}{6} + \dfrac{4}{6} =\dfrac{1+4}{6} =\dfrac{5}{6}$

e)  $\dfrac{^{4)}3}{\ 5} + \dfrac{1}{20} =\dfrac{12}{20} + \dfrac{1}{20} = \dfrac{12+1}{20} =\dfrac{13}{20}$