Question

Tema chimie ajutor pls​

Answer 1

Răspuns:

1).m MgO =?

mMg=80g  Mg

mO₂ =?

Masele moleculare

MMg=24g/ mol,  MMgO=24=16=40g/mol, MO₂=2ˣ16=32g/mol

2Mg+ O₂→  2MgO

2ˣ24gMg...................2ˣ40gMgO

80gMg...........................X

X=  80ˣ2ˣ40/ 2ˣ24= 133,33 g MgO

număr de moli  n=m/M

n=133,33/40= 3,33 moli MgO

2ˣ24gMg...................32 g O₂

80gMg...........................Y

Y=  80ˣ32/2ˣ24=  53,33 gO₂

n=m/M

n= 53,33/32=1,66 moli O₂

2). CaCO₃     +     H₂SO₄→  Ca SO4+  H₂CO₃

H₂CO₃→  H₂O+ CO₂

-masele moleculare

MH₂SO₄=(2ˣ1)+  32+( 4ˣ16)= 98g/mol

MCaSO₄=  40+32+ 4ˣ16=  136g/mol

MH₂O= (1ˣ2)+ 16=18g/mol

MCO₂ = 12+2ˣ16=44 g/mol

98g H₂SO₄.....................136gCaSO₄...............18gH₂O................44gCO₂

24g H₂SO₄............................X..................................Y..........................Z

X=24ˣ136/ 98 = 33,30gCaSO₄

Y=24ˣ18/98=4,40gH₂O

Z= 24ˣ44/98=10,77 gCO₂

MM

Explicație: