Question

Tema de la chimie. Tot subiectul G.

Answer 1

1. (CH2O)n = 150 => 12n+2n+16n = 150 => 30n=150 => n=5  -> F.M = C5H10O5

2. MCH4O = 32g/mol

%C=mC/M*100 = 12/32*100 =Calculeaza !!

%H=mH/M*100 = 4/32*100 = 

%O=16/32*100 = 

3. %O=100-52,17-13,04=34,79

C=52,17/12 = 4,3475 ||:2,174 => 2 atomi C

H = 13,04/1 = 13,04 => 6 atomi H

O=34,79/16=2,174  => 1 atom O

F.B -> (C2H6O)n 

F.M => 24n+6n+16n=46 => 46n=46 =>n=1 -> C2H6O

F. structurala -> CH3-CH2-OH

4. C3H8O , NE=0                 CH2(OH)-CH2-CH3

CH3-CH-CH3
         |
        OH

5. dgaz=M/Mgaz => M=1,038*28,9=30g/mol

%C=100-20=80%

nC=%C*M/AC*100 = 80*30/1200 = 2 atomi C

nH =%H*M/AH*100 = 20*30/100 = 6 atomi H

F.M -> C2H6 -etanul