Question

Testul 1 va rog mult dau coronita

Answer 1

Partea1.
1.d
2.b
3.c
4.b
5.d
6.b
7.d
8.b
9.a
Partea a 2a.
1.
100:[110:5-96:(203-65*3)]=100:[110:5-96:(203-195)]=100:(110:5-96:8)=
=100:(22-12)=100:10=10
2.
a)2/3> n/3        b) 5/4< 5/9
3n< 6                    5n>20
n<2                          n>4
n∈(-∞; 1)                n∈(5;+∞)

3.
2p+5c=95  -
2p+3c=65
--------------
/      2c= 30; c=30:2; c=15.⇒ 1c=15 lei(a)

2p+3*15=65
2p=65-45
2p=20 lei (b)

2*20+7*15= 40+105=145 lei (c)

Answer 2

I.
1 D
2B
3 A
4 B
5A
6B
7D
8B
9A
II.
100:[110:5-96:[203-65*3)]
=100:[22-96(203-95)]
=100:[22-96:8}
=100:(22-12)
=100:10
=10
problema cu carti si penare
2p+5c=95
2p+3c=65
le scadem
2p-2p+5c-3c=95-65
2c=30 deci c=15
2p=95-5c=95-75
p=10
1 carte= 15 lei,. un penar 10 lei
c)4p+7c=4*20+7*15=80+105=185 lei