Question

Testul 4 exeritiul 1 va rog repde

Answer 1

$Din~multimea~A={... \frac{5}{x+2} ...} ,~rezulta~ca~:\frac{5}{x+2} \\ Deci~x+2~apartine~D5=[+-1,+-5] \\ x+2=1=\ \textgreater \ x=-1 \\ x+2=-1=\ \textgreater \ x=-3 \\ x+2=-5=\ \textgreater \ x=-7 \\ x+2=5=\ \textgreater \ x=3 \\ \\ A=[-1,-3,-7,3] \\ Multimea~B! \\ -1\ \textless \ 2x+1\ \textless \ 3 |-1 \\ -2\ \textless \ 2x\ \textless \ 2 |:2 \\ \\ -1\ \textless \ x\ \textless \ =1 \\ \\ B=[0,1] \\ A~si~B-multimi~disjuncte!$