Question

$0.5 + 8 \times ( \frac{1}{4 } + ( \frac{7}{12} - \frac{1}{24} ) \ \div 8 \frac{2}{3}$
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Answer 1

Răspuns:

$\bf0.5 + 8 \cdot \bigg( \dfrac{1}{4 } + \bigg(\dfrac{7}{12} - \dfrac{1}{24} \bigg)\div 8 \dfrac{2}{3}\bigg) = </p><p>$

$\bf \dfrac{5}{10} + 8 \cdot \bigg( \dfrac{1}{4 } + \bigg(\dfrac{7 \cdot2}{24} - \dfrac{1}{24} \bigg)\div \dfrac{8 \cdot3 + 2}{3}\bigg) =$

$\bf \dfrac{5}{10} + 8 \cdot \bigg( \dfrac{1}{4 } +\dfrac{14 - 1}{24}\div \dfrac{24 + 2}{3}\bigg) =$

$\bf \dfrac{5}{10} + 8 \cdot \bigg( \dfrac{1}{4 } +\dfrac{13}{24}\div \dfrac{26}{3}\bigg) =$

$\bf \dfrac{5}{10} + 8 \cdot \bigg( \dfrac{1}{4 } +\dfrac{13}{24}\cdot \dfrac{3}{26}\bigg) =$

$\bf \dfrac{5}{10} + 8 \cdot \bigg( \dfrac{1}{4 } +\dfrac{ \not13}{ \not24}\cdot \dfrac{ \not3}{ \not26}\bigg) =$

$\bf \dfrac{5}{10} + 8 \cdot \bigg( \dfrac{1}{4 } +\dfrac{ 1}{8}\cdot \dfrac{1}{2}\bigg) =$

$\bf \dfrac{5}{10} + 8 \cdot \bigg( \dfrac{1}{4 } +\dfrac{ 1}{16}\bigg) =$

$\bf \dfrac{5}{10} + 8 \cdot \dfrac{4 + 1}{16} =$

$\bf \dfrac{ \not5}{ \not10} + 8 \cdot \dfrac{5}{16} =$

$\bf \dfrac{1}{2} + \not8 \cdot \dfrac{5}{ \not16} =$

$\bf \dfrac{1}{2} + \dfrac{5}{2} =$

$\bf \dfrac{1 + 5}{2}=$

$\bf \dfrac{ \not6}{ \not2}=$

$\boxed{\boxed{\bf 3}}$