Question

$( {10}^{2} - {8}^{2} ) \div 6 \div 2 + {1}^{2019}$
Va rog pana la si 54​

Answer 1

$( {10}^{2} - {8}^{2} ) \div 6 \div 2 + {1}^{2019}$

$(100 - 64) \div 6 \div 2 + 1$

$36 \div 6 \div 2 + 1$

$6 \div 2 + 1$

$3 + 1$

$4$

Answer 2

(100- 64) : 6 :2+1
36:6:2+1
6:2+1
3+1=4